- Información
- Chat IA
Tarea 3. Isomeria Constitucional y Estereoisomeria Geometrica
Química orgánica (H182)
Universidad del Valle de México
Comentarios
- amazing work. thank you.
Otros documentos relacionados
- A4 JGHE - actividad 4 quimica
- Actividad 11. Proyecto Integrado Etapa 1, 2 y 3 EQP 6
- Volcanes
- A#4 Química - Etapa 1. Descripción de la problemática Clasificación de las sustancias puras,
- Quimica A1 - Mapa conceptual de la materia, con su clasificacion (sustancias puras y mezclas)
- U5A11 PI3 - Proyecto integrador etapa 2, quimica uvm
Vista previa del texto
Tarea 3. Isomeria Constitucional y Estereoisomeria Geometrica
Due: 11:59pm on Saturday, September 5, 2020 To understand how points are awarded, read the Grading Policy for this assignment.
Isomería estructural
Learning Goal: Identificando isómeros de posición, cadena o funcionales
Part A - El siguiente par de compuestos respresentan un par de isómeros
ANSWER:
Correct
Part B -
El siguiente par de compuesto respresenta un par de isómeros
ANSWER:
Correct
Part C - ¿Cuáles de las siguientes estructuras representan compuestos que son isómeros estructurales del n-heptano?
ANSWER:
funcionales estereoisómeros de cadena de posición
de posición estereoisómeros de cadena funcionales
All attempts used; correct answer displayed
Isomers constitutional
Isomers are molecules with the same chemical formula, but different structures.
Part A Which choice is a constitutional isomer of this molecule?
Hint 1. How to approach the problem If you were holding a molecular model of this compound in your hand, you would have to pull it apart and reform it in some other arrangement to produce a constitutional isomer. Flipping the molecule over horizontally or vertically would not produce a consitutional isomer. Also, rotation around carbon-carbon single bonds does not result in constitutional isomers.
ANSWER:
Correct
Isomería estructural
Learning Goal: Identificar cuales son o no isómeros
a b c d e
Part B sec-butyl bromide Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default. ANSWER:
Correct
Part C isobutyl bromide Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default. ANSWER:
Correct
Part D tert-butyl bromide Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default. ANSWER:
Draw the molecules on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default. ANSWER:
Correct
Part C Draw trans isomer for the following compound.
Draw the molecules on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default. ANSWER:
Correct
Part D Draw cis isomer for the following compound.
Draw the molecules on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default. ANSWER:
Correct
Chapter 4 Problem 2
Part A What is the relationship between the following compounds?
ANSWER:
Correct
Problem 4 - Enhanced - with Feedback
Assign relative priorities to each set of substituents: You may want to reference (Pages 148 - 150) Section 4 while completing this problem.
╱C=and=
H
CH╲ 3
C╲
Br
╱H
╱C
CH 3
H╲
C╲
Br
╱H
conformational isomers positional isomers structural isomers stereoisomers constitutional isomers
Part A
Rank from largest to smallest. To rank items as equivalent, overlap them. ANSWER:
Correct The relative priority of the group depends on the atomic number of the atom directly bonded to carbon. When comparing groups, the atom with the higher atomic number has a higher priority. Iodine (atomic number 53) has the highest priority, which is followed by chlorine, then hydroxide (the atomic number of oxygen being 8), and the hydrocarbon group has the lowest priority because the atomic number of carbon is 6. Relative group priority is used to determine whether a configuration isomer of an alkene would have an E or Z notation, and it is also used to determine whether an enantiomer (with a chiral center) would have the R or S notation.
Part B
Rank from largest to smallest. To rank items as equivalent, overlap them. ANSWER:
−Cl−I−OH−C 3 H 8
Reset Help
The correct ranking cannot be determined.
−OH−OH−Br−CH=CH 2 CH 2 CH 2 CH 2
−I −Cl −OH −C 3 H 8
Highest priority Lowest priority
Correct
Cycloalkanes: Selecting cis positions in chair perspective
Part A Using the chair perspective of cyclohexane shown in the figure, select all of the positions that are cis to position #1.
Select all that apply. ANSWER:
Correct Note that groups don't have to be parallel to one another to be considered cis; in fact, equatorial groups on adjacent carbons are only 60 apart, yet they are trans. What matters is which face of the ring the substituents are on. The axial position on one carbon is cis to the equatorial position on the two neighboring carbons, and vice versa.
Problem 4.
Draw the cis and trans isomers for the following:
Part A 1-bromo-4-chlorocyclohexane Draw the molecules on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default. Show the appropriate stereochemistry by choosing the dashed or wedged buttons and then clicking a bond on the canvas. ANSWER:
2 3 4 5 6 7 8 9
10
11
12
∘
All attempts used; correct answer displayed
Chapter 4 Problem 5
Part A What is the relationship between the structures shown below?
ANSWER:
Correct
Chapter 3 Reading Question 1
Part A
enantiomers constitutional isomers conformational isomers diastereomers configurational isomers
How many constitutional isomers have the molecular formula C 6 H 14?
Hint 1. How to quickly generate isomers of simple alkanes Begin with a straight chain of carbon atoms. Shorten the chain by one carbon and add a one-carbon branch at all unique carbons. Then, shorten the chain by two carbons and two one-carbon branches and try a two-carbon branch, remembering to focus on the longest chain.
ANSWER:
Correct
Score Summary:
Your score on this assignment is 86%. You received 86 out of a possible total of 100 points.
3
5
6
4
Tarea 3. Isomeria Constitucional y Estereoisomeria Geometrica
Materia: Química orgánica (H182)
Universidad: Universidad del Valle de México
- Descubrir más de:
Otros estudiantes también vieron
Otros documentos relacionados
- A4 JGHE - actividad 4 quimica
- Actividad 11. Proyecto Integrado Etapa 1, 2 y 3 EQP 6
- Volcanes
- A#4 Química - Etapa 1. Descripción de la problemática Clasificación de las sustancias puras,
- Quimica A1 - Mapa conceptual de la materia, con su clasificacion (sustancias puras y mezclas)
- U5A11 PI3 - Proyecto integrador etapa 2, quimica uvm