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ALEKS Note : Combustion Analysis
Course: General Chemistry (CHEM 142)
127 Documents
Students shared 127 documents in this course
University: University of Washington
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Combustion
Analysis
1)
Man
to
mole
conversion
to
get
moles
of
CO2
produced
moles
coz
=
mass
CO2
molar
mass
coz
2)
Man
to
mole
conversion
to
get
moles
of
H2O
produced
moles
Hyo
=
mass
Huo
x
2
since
there
are
2
H
moles
molar
mass
Hyo
in
each
H2O
3)
Moles
to
mass
conversion
for
both
C
and
H
man
C
=
(
mole
,
c)
(
molar
mass
C
)
mass
H
=
(
mows
H
)
(
molar
mass
H
)
4)
subtract
masses
from
total
man
to
find
man
of
O
5)
If
there
is
man
leftover
,
convert
man
to
0
miter
,
if
not
,
go
straight
to
doing
mole
ratio
mm
coz
=
44
.
OI
mm
Hyo
=
18
.
02
Moler
C
:
.
6250852879
1.25×4
g-
+
z
man
-
-
7
.
51
moles
H
:
.
499445061
I
mass
-
-
.
5
moles
0
:
man
-
-
O
Clo
H
8